8x+8=12x^2

Solution for 8x+8=12x^2 equation:

8x+8=12x^2

We move all terms to the left:

8x+8-(12x^2)=0

determiningTheFunctionDomain
-12x^2+8x+8=0

a = -12; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·(-12)·8
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{7}}{2*-12}=\frac{-8-8\sqrt{7}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{7}}{2*-12}=\frac{-8+8\sqrt{7}}{-24}
$